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Re: Filter Choke Design



> Proof: (for single coil)
> E dt = NA dB => dB/dT = E/NA
> let voltage between the ends of the coil be low like it is for low
> freq. signals. Then magnetic flux will be low too. On the other hand,
> for high freq. E will be signifficant when the coil is ringing and
> dB/dt will lead to change in magnetic flux.

It's been years since I've had any physics, but dB/dt is the change in 
magnetic field wrt/time, not the magnetic flux itself.  A Dc current is 
great at producing magnetic flux, the flux just doesn't have any time 
varying component.


Steven Roys (sroys-at-radiology.ab.umd.edu)