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Re: Real data from real experiments.



Tesla List wrote:
> 
> > Subject: Real data from real experiments.
> 
> >From bturner-at-apc-dot-netThu Nov  7 22:27:35 1996
> Date: Thu, 07 Nov 1996 03:58:57 -0800
> From: open_minded <bturner-at-apc-dot-net>
> To: tesla-at-pupman-dot-com
> Subject: Re: Real data from real experiments.
> 
> Tesla List wrote:
> >
> > >From hullr-at-whitlock-dot-comWed Nov  6 22:31:19 1996
> > Date: Wed, 06 Nov 1996 11:38:55 -0800
> > From: Richard Hull <hullr-at-whitlock-dot-com>
> > To: tesla-at-pupman-dot-com
> > Subject: Real data from real experiments.
> >
> > All,
> >
> > I took the time out to repeat two experiments which few seemed to do but
> > a lot have commented on.  I performed the first experiment presented here
> > over a year ago and the latter experiment 5 years ago.  So I repeated
> > with fresh data and first rate instrumentation.
> >
> 
> <SNIP>
> 
> > Conclusion:
> >
> > The voltage on any capacitor discharging into an identical capacitor with
> > divide by 1/2 or equal 50% of its original voltage regardless of massive
> > blasting of copper to molten beads in the exchange or a kinder, gentler
> > flow of charge through limiting resistances.  1/2 of the original stored
> > energy (1/2cv^2) is aboslutely and irrevocably lost in this situation to
> > a plethora of forms of waste energy given off to the evironment and
> > circuit components.  Charge is conversed as well as energy.  The energy
> > transfer to the other capacitor will forever undergo a 50% loss factor.
> 
> > DO THE EXPERIMENT!  (Benjamin Franklin)
> >
> > Richard Hull, TCBOR
> 
> Richard, et al:
> 
>  Thanks for the effort in duplicating the experiment. I do have one
> comment, and that is on the subject of capacitive voltage division:
> 
> "When two identical capacitors are hooked in series, where does 1/2
> of the capacitance go?">

 - Brent
> 
> It really didn't go anywhere it is still there but in each cap examined singly only.  The series pair has effectively doubled the dielectric 
thickness. and thus halved the capacitance.   This question is like 
asking where the resistance goes when two 2 ohm resistors are placed in 
parallel to yield only 1 ohm.  The current divides equally.  In the above 
example the voltage divides equally.
> 

Richard Hull, TCBOR