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Re: Hi Q Quest (was sync TC latest resul




From: 	Benson_Barry%PAX5-at-mr.nawcad.navy.mil[SMTP:Benson_Barry%PAX5-at-mr.nawcad.navy.mil]
Sent: 	Saturday, November 15, 1997 3:46 PM
To: 	tesla-at-pupman-dot-com
Subject: 	Re: Hi Q Quest (was sync TC latest resul


Hi John, All,
     Thanks for the good data.

     I wonder about something.  The toroid has
isotropic capacity.  Since Xc = 1/(2 * pi * f * C) the toroid
could be viewed as a reactive load that gets bigger as
frequency gets higher.  In other words it would require
more energy to charge the toroid to a given voltage as
the frequency increased.  If you had a 100 kHz coil and
a 200 kHz coil with the same size toroid then the 200 kHz
coil would require more energy to get the same spark length
at the same break rate to obey the law of conservation of energy.

     To eliminate the resistance variable between the two
coils they would have to be wound with different sizes of wire.
Need Rac the same for a valid energy comparison.

     To keep the isopropic capacity of the toroid the same
for the two coils they would have to be the same height and
wound on the same diameter form of the same material.

     The inductance of the 100 kHz coil would have to be
higher than the 200 kHz coil.  This would add inductance as
a variable to the comparison.

     The larger inductance would have a greater
reactance Xl = 2 * Pi * f * L which would add this variable to
the comparison.

     Since Q = (2 * Pi * f  * L) / Rac at resonance then
the Q of the 100 kHz coil would be higher.  This adds a third
variable to the comparison!

     Now Rac is the same for both coils and the current
that flows at resonance is limited by the Rac only (?) .  The
voltage at which the spark begins to break out of the toroid
should be the same determining Vtoroid. This sets the maximum
amount of charge that can be stored in the toroid.  With this
the current that flows is determined by how fast the charge in
the toroid drains and refills.  Since I = dQ / dT a greater average
current flow will be required to charge the toroid of the 200 kHz
coil.  The energy E = 1/2 * L * (I^2)  stored in the magnetic field
of the 200 kHz coil will be greater as the current has increased by
a constant factor of the frequency  while the inductance has
decreased by a factor the square root of the frequency (the
current increases faster than the inductance increases).

     The primary tank capacitor would have to be the same
capacitance and charged to the same voltage with a DC power
supply that was disconnected before discharging the capacitor
into the primary inductor before a level comparison could be
performed of spark VS toroid size VS input energy VS etc.

                         Barry

 ----------
"Hmmm,  I'd have to get a new form, or add some sort of extension
to my existing form.  I have 3 secondaries; one is 6 1/2" by 23", #28,
80kHz, gives 42" spark with small toroid, and 44"? spark with
the large toroid.  Another sec. is 4 1/4" by 23" , #28, 130 kHz, gives
40" spark with small toroid, and 46" spark with large toroid.  And
third sec. is 17" by 17", #24, 110kHz, gives 42" with small toroid,
and 44" with large toroid.  Does this all fit your scenario concerning
the Xc issue?

John Freau"