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Re: Medhurst Formula (fwd)
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To: tesla@pupman.com
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Subject: Re: Medhurst Formula (fwd)
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From: Tesla List <mod1@pupman.com>
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Date: Fri, 7 Aug 1998 20:59:52 -0600 (MDT)
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Approved: mod1@pupman.com
---------- Forwarded message ----------
Date: Fri, 7 Aug 1998 13:09:15 -0600
From: "D.C. Cox" <DR.RESONANCE@next-wave.net>
To: Tesla List <tesla@pupman.com>
Subject: Re: Medhurst Formula (fwd)
to: Mike
Very interesting. Us and others have also noted these curious results --
it just seems to keep getting closer to 3.14159. Hmmmm indeed.
DR.RESONANCE@next-wave.net
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> From: Tesla List <tesla@pupman.com>
> To: tesla@pupman.com
> Subject: Re: Medhurst Formula (fwd)
> Date: Thursday, August 06, 1998 9:52 PM
>
>
>
> ---------- Forwarded message ----------
> Date: Thu, 6 Aug 1998 00:44:03 EDT
> From: ESchulz531@aol.com
> To: tesla@pupman.com, Hollmike@aol.com
> Subject: Re: Medhurst Formula (fwd)
>
> Hi Mike,
> I did a little thinking.
> Since (from you) Cself = 0.256479 * H + 0.78646 * D. If you
> set H = 0.78646 and D = 0.256479 you will get the largest coil
> (as in most wire which leads to more inductance) for a given
> amount of capacitance. It just so happens that H / D or
> 0.78646 / 0.256479 = 3.06637. So this would suggest a
> reason to use a height to diameter ratio of 3. Hmm
>
> Just a thought.
>
> Erik Schulz