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NST Max Ratings and Mains Resonance (fwd)




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From:  Malcolm Watts [SMTP:MALCOLM-at-directorate.wnp.ac.nz]
Sent:  Sunday, February 15, 1998 6:50 PM
To:  Tesla List
Subject:  Re: NST Max Ratings and Mains Resonance (fwd)

Hi Alfred,

> Date: Sat, 14 Feb 1998 11:24:38 -0500
> From: "Alfred C. Erpel" <aerpel-at-op-dot-net>
> To: Tesla List <tesla-at-pupman-dot-com>
> Subject: Re: NST Max Ratings and Mains Resonance (fwd)
> 
 
> 
> +AD4-
> +AD4-
> +AD4----------- Forwarded message ----------
> +AD4-Date: Thu, 12 Feb 1998 15:54:09 -0500
> +AD4-From: Thomas McGahee +ADw-tom+AF8-mcgahee+AEA-sigmais-dot-com+AD4-

> +AD4-Subject: NST Max Ratings and Mains Resonance
> +AD4-
> +AD4-Bill, Malcolm, and other interested coilers,
> +AD4-Besides the resonant rise that Malcolm mentions, there is also 
> +AD4-the fact that when the main cap and the transformer are set to
> +AD4-resonate at the mains frequency, the transformer is capable
> +AD4-of providing current levels that are several times the usual 
> +AD4-'current-limited' value. If the wire in the secondary is too
> +AD4-thin, then you can actually burn out the secondary winding
> +AD4-under these mains-resonant conditions.
> +AD4-
> +AD4-Thus, with the proper resonant conditions a 15KV 60 MA
> +AD4-NST can charge the mains cap up to voltages in excess of
> +AD4-40KV, and at a rate that is much greater than the 60 MA
> +AD4-rating would suggest. Note that both the extra voltage and
> +AD4-extra current can contribute to the NST failing prematurely.
> +AD4-
> +AD4-Hope this helps.
> +AD4-Fr. Tom McGahee
> 
> 
 
>     Hello,
> 
>     It is my understanding that in a series resonant circuit, the
> capacitive reactance and inductive reactance exactly cancel out, leaving
> only the pure resistance (ohms) as the total circuit impedance.
> Therefore,(at resonance) the current (I) flowing in the circuit is
> determined by I+AD0-E/R where E +AD0- input voltage (to the series
> resonant circuit) and R +AD0- ohms resistance of the circuit. 
> 
>     My point is, I can see how power (EI) is increased in an inductive
> circuit because voltage is increased (and of equal value) measured across
> the capacitor and inductor, but the current (I) flowing in the circuit has
> not changed.
>     What resonant conditions allow/cause an increased current flow?

If the voltage across a component (resistive or reactive) increases, 
surely the current through it must have increased if the frequency and 
component values haven't changed?

Malcolm