Re: resistance in an LRC circuit used to calculate time constant

• To: tesla-at-pupman-dot-com
• Subject: Re: resistance in an LRC circuit used to calculate time constant
• From: "Antonio Carlos M. de Queiroz" <acmq-at-compuland-dot-com.br> (by way of Terry Fritz <twftesla-at-uswest-dot-net>)
• Date: Wed, 15 Mar 2000 20:25:14 -0700
• Approved: twftesla-at-uswest-dot-net
• Delivered-To: fixup-tesla-at-pupman-dot-com-at-fixme

Tesla List wrote:
 
> Original Poster: "Malcolm Watts" <malcolm.watts-at-wnp.ac.nz>

> However, it is strictly true. The gap can be treated as a voltage
> source and therefore be ignored (unless one gets very picky). The
> reason is that gap conduction voltage is rather more constant over a
> range of currents (consider a sinusoidal signal)  than the voltage
> across a resistance would be.

Something strange... The gap obviously dissipates energy, and
the voltage across it changes polarity at each semicycle. It is
a nonlinear resistor, but it is a resistor. It can be replaced
by an equivalent linear resistor that dissipates the same amount
of energy. An interesting theoretical consideration is if a
nonlinear resistor that keeps a constant voltage across it,
only changing the polarity of the voltage in response to the
current, changes the oscillation frequency of an LC circuit.

Antonio Carlos M. de Queiroz

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