Re: cockcroft-walton question

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Crow Leader by way of Terry Fritz <teslalist-at-qwest-dot-net>" <tesla-at-lists.symmetric-dot-net>

Sent: Saturday, May 17, 2003 10:20 PM
Subject: Re: cockcroft-walton question


 > Original poster: "by way of Terry Fritz <teslalist-at-qwest-dot-net>"
<dhmccauley-at-spacecatlighting-dot-com>
 >
 >
 > No.  What I actually was meaning to say was, "components should be rated
 > *according* to the input voltage on all stages."  In example, you only use
 > the input voltage specifications to
 > determine your component ratings as opposed to using the output voltage
 > specifications of the multiplier.
 >
 > The Captain

Your original post:

 >  >  > No.  Each stage sees approximately the same voltage so all the stage
 >  >  > components should be rated identically.
 >  >  > For example, if you plan to use a 12kV/30mA NST for your input power
 >  > supply
 >  >  > and use one output only from the NST (6kVAC = 8.5kV peakV), your
 >  > components
 >  >  > should be rated
 >  >  > for at least the input voltage on all stages.

Sort of sounds like "your parts can be rated 8.5kV in this case", which is
not right.
KEN

 >  >
 >  > No.
 >  >
 >  > Rectifiers must be should be rated no less than TWICE input voltage for
 > such
 >  > a multiplier. Take a look at the first stage. One cycle charges the
first
 >  > cap though the first diode. Then the AC voltage reverses, and there is
now
 >  > peak lin voltage + charged capacitor voltage across that first diode.
This
 >  > process repeats for each stage you have. Multipliers work by "adding"
line
 >  > voltage to each previously charged stage of capacitors. As each stage
has
 >  > charged, the additional voltage from the input then goes to charge the
 > next
 >  > cap.
 >  >
 >  > KEN
 >  >
 >  >
 >  >
 >  >
 >  >
 >
 >
 >