Re: Javatc update to version 10.j

["Tesla list" <tesla@xxxxxxxxxx>]

Original poster: Esondrmn@xxxxxxx 

Matt,

Good point.  Not used to seeing it in that form.  Sorry about that 
Bart.  You wrote one thing and my eye told me something else.

Ed Sonderman

In a message dated 12/6/2005 9:48:27 AM Pacific Standard Time, 
tesla@xxxxxxxxxx writes:
Original poster: Mddeming@xxxxxxx

Hi Ed,
     Actually since he is dividing by 5/9, he is correct. It would be
equivalent to multiplying by 9/5.   (centigrade*(9/5)+32) is the same
as (centigrade/(5/9)+32). It confused me for a minute too.
Matt D.




In a message dated 12/5/05 6:15:49 P.M. Eastern Standard Time,
tesla@xxxxxxxxxx writes:
Original poster: Esondrmn@xxxxxxx

Bart.

A typo I suspect.  Centigrade to Fahrenheit should be:
To convert from Centigrade to Fahrenheit:  (centigrade/(9/5)+32)

9/5 as opposed to 5/9.

Ed Sonderman