# Re: simple reactance calculations

```Original poster: "Barton B. Anderson" <bartb@xxxxxxxxxxxxxxxx>

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The equation you showed was Xc = 1/(2*pi*f*C). If you know you want 5 ohms of reactance, then you to solve for C since that is the unknown.
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C = 1/(2*pi*f*Xc)

With Xc of 5 ohms at 60Hz, C = 1/(2*pi*60*5) = 530.5 uF

Does Xc increase when C is decreased? Yes.

With Xc of 10 ohms at 60Hz, C = 1/(2*pi*60*10) = 265.3 uF

Take care,
Bart

Tesla list wrote:

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```Original poster: "Langer Giv'r" <transworldsnowboarding19@xxxxxxxxxxx>

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Hello, I am having some trouble finding the capacitive reactance for a capacitive current limiter. Im sure the problem is a small error that i am frequently overseeing but still I am stumped. I want to get about 5 ohms reactance from a capacitor, but i do not know what capacitance to use
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with 0.95uF, and using the reactance formula, it says i get 2792 ohms of reactance, which is obviously wrong. 1 / ((2)(pi)(f)(Capacitance))
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Does anyone have a solution for this? and also, is it true that capacitive reactance increases as capacitance is decreased?
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thanks

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