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Re: Identifying Current and Voltage on vaguely marked MOT. (fwd)
---------- Forwarded message ----------
Date: Mon, 27 Aug 2007 12:46:52 -0400
From: David Speck <Dave@xxxxxxxxxxxxxxxx>
To: Tesla list <tesla@xxxxxxxxxx>
Subject: Re: Identifying Current and Voltage on vaguely marked MOT. (fwd)
Watts is (approximately) volts x amps. Not entirely straightforward in
setups where you are driving inductive loads where current and voltage
are not precisely in phase, but close enough for our approximation.
If you determine the output voltage of your MOT, often by driving the
secondary with a known voltage, and then measuring the voltage on the
input windings, then you can determine the turns ratio and calculate
what the nominal output voltage will be when the primary is driven by
120 VAC. Divide 700 by the voltage, and you will get an estimate of the
A MOT can deliver more than its rated current for a short time, but will
get hot faster if overloaded, and it may burn out. Also, MOTs come with
magnetic shunts which will provide a degree of current limiting, but not
enough to withstand a prolonged short circuit like a NST can sustain.
There is also a formula to estimate the wattage capability of a
laminated steel core transformer based on the cross section area of the
center of the core. VA Rating = ((Core Cross section area (sq in))/0.16)^2.
Tesla list wrote:
> ---------- Forwarded message ----------
> Date: Mon, 27 Aug 2007 00:21:46 -0500
> From: Glen McGowan <glen.mcgowan@xxxxxxxxx>
> To: Tesla list <tesla@xxxxxxxxxx>
> Subject: Identifying Current and Voltage on vaguely marked MOT.
> Just curious if there's some super secret math out there that can help me
> identify the rated voltage and current of a MOT. I only have one variable
> for the equations.... the MOT is labeled with 700W output. That's it......