[TCML] charging reactors
bartb at classictesla.com
Thu Mar 5 19:59:40 MST 2009
Tesla, well, would have been stuck with cotton covered wire. But if he
had access to todays magnet wire, probably small and compact as possible.
Interesting inductance script. However, either my calc's are wrong or
the script calc's are wrong for the inductance.
For multilayer, I'm using the following:
LuH = (31.6 x n^2 x ri^2) / (6 x ri + 9 x L + 10 x (ro-ri))
n = total turns
ri = inside coil radius
ro = outside coil radius
L = coil length
(all in meters)
Quite a discrepancy between the script inductance result and the above.
For the calculators inputs at 5H, he realizes 51.18 layers. If I use 24
awg (.0213" in his code) and adjust my layers the same, everything works
out fine (id, od, dcr, turns, wire length, etc..) except I show 1.75H
where he shows 5H (2"D, 4.75"L, 24G). Somethings odd here... and can't
put my finger on it.
Anyone else have a known working multilayer calculation for L?
Jim Harvey (UDN) wrote:
> For what its worth, I wondered "What would Tesla do?" If he needed an
> inductor, he didn't worry too much about space in his lab or the cost of
> My thought was, hey, just make it bigger in diameter since L goes up
> (approximately, for large diameters) by the square of the diameter.
> My initial calculations tell me that larger diameter will break the bank in
> terms of total wire length.
> In my search, I found this:
> Any way, just thoughts for a snowing morning here in Utah.
> Jim Harvey, W7YV
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