Re: Energy vanishing into air? (fwd)

[Steven Roys <sroys@xxxxxxxx>]

---------- Forwarded message ----------
Date: Sun, 18 Jan 2004 09:00:44 +0200
From: gtyler <gtyler@xxxxxxxxxxxxxxx>
To: High Voltage list <hvlist@xxxxxxxxxx>
Subject: Re: Energy vanishing into air? (fwd)

I think you need to look at Q=CV; as the capacitance is decreased the
voltage increases as the charge is constant. This is how a Van de Graaff
Gen. operates. Also, as The energy is 1/2 CV squared the energy
increases, and this increase in energy is supplied by the tourque on the
shaft. There is nothing for nothing.

George Tyler

----- Original Message -----
From: "High Voltage list" <hvlist@xxxxxxxxxx>
To: <hvlist@xxxxxxxxxx>
Sent: Saturday, January 17, 2004 11:19 PM
Subject: Energy vanishing into air? (fwd)


> Original poster: Steven Roys <sroys@xxxxxxxx>
>
>
>
> ---------- Forwarded message ----------
> Date: Sat, 17 Jan 2004 11:54:14 -0500
> From: Alfred Erpel <alfred@xxxxxxxxx>
> To: High Voltage list <hvlist@xxxxxxxxxx>
> Subject: Energy vanishing into air?
>
>
>
> Howdy All,
>
>     Imagine an air variable capacitor with plates fully engaged and
the
> capacitor fully charged.
>
>     Let's use the example of .001µF charged to 10,000 volts. Stored
energy =
> joules = .5CV^2 = .05 watt=seconds.
>
>     What happens to the energy of the fully charged capacitor when the
> plates are rotated to the 0µF capacitance position?
>
> Regards,
>
> Al Erpel
>
> [Potential energy.  It would take that much energy to rotate the cap
> plates to the 0uF position (barring friction losses), and rotating
them
> back would convert the energy back from potential to the energy stored
in
> the electrical field.  SRR]
>
>
>