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Re: Re[2]: Neon power draw, and resonant stresses.




From: 	NTesla[SMTP:ntesla-at-ntesla.csd.sc.edu]
Reply To: 	ntesla-at-ntesla.csd.sc.edu
Sent: 	Tuesday, September 02, 1997 11:24 AM
To: 	tesla-at-pupman-dot-com
Subject: 	Re: Re[2]: Neon power draw, and resonant stresses.


>
>At 08:50 AM 8/29/97 -0500, you wrote:
>>
>>From: 	FutureT-at-aol-dot-com[SMTP:FutureT-at-aol-dot-com]
>>Sent: 	Friday, August 29, 1997 4:22 AM
>>To: 	tesla-at-pupman-dot-com
>>Subject: 	Re: Re[2]: Neon power draw, and resonant stresses.
>>
>>In a message dated 97-08-28 15:56:55 EDT, you write:
>>
>><< 
>>> John, you have brought up an issue I had asked the list about and never 
>>> got a response.  You say "If it's value is such that it resonates with 
>>> the leakage reactance of the neon trannie..." How is this determined. In 
>>> the designing phase how could one determine if this would happen? And 
>>> does this stress the neon two much, or is it ok as long as the gap fires 
>>> to discharge it?
>> 
>>> Still resonating in Ohio,
>>> Mad Coiler
>>>  >>
>>
>>Mad,
>>
>>I'm unable to find the formula, I was hoping someone would re-post
>>it for you again.  "does it stress the neon too much?"... depends on
>>what you mean by too much.  Certainly, it stresses it more than
>>without resonant charging.  Yes, by limiting the gap spacing, you can
>>limit the voltage across the trannie, and still obtain the benefit of
>>the increased current draw. None of my neons have yet burned, 
>>and I've been using this resonant method for years.  
>>(I did burn out a couple of neons...but that was when I used a 
>>non-sync rotary gap!)
>>
>>John Freau

C=(10^6)/(2*pi*f*Z)

Where:
C=capacitance in uF
f=frequency (50 or 60 Hz)
Z=transformer impedance (typically V/I) 

You can find I if you have to, by dividing the total output of the xformer
in Watts buy it's maximum output voltage.

Example:

15000V -at- 60mA (15000/0.060) yields Z, therefore (in this case) Z=250000

So now:

C=(10^6)/(2*pi*f*250000)

at 60 Hz:

C=(10^6)/(2*pi*60*250000) = (10^6)/(377*250000) = (10^6)/94250000 = ~0.0106uf

So, 0.01uF would be a good match for that particular transformer for
resonance at 60Hz.

Corrections welcome :)   (This is the ONLY formula I ever derived all by my
myself ;)

Dan

>