Inductance (fwd) [correction]
From: Alan Sharp [SMTP:AlanSharp-at-compuserve-dot-com]
Sent: Thursday, April 02, 1998 3:50 AM
Subject: Inductance (fwd) [correction]
> Sorry to say this but there is a formulaic error in your snip<
Its more than possible - the alagbra circuits could have got
fried along with the calculus neurons.
but I just did it again with pencil and paper - rather than
directly on the screen and it checks out, and I looked again
at Bylund he also comes to h=0.9r.
There is a typo in the original script N = b / d is N = b * d
but Erik got to the right result. Must have been a copy
error. But however we have got there, we have now two
Maximum L when h = 0.9 * r
or h/d = 0.45
And you supply:
Maximum Q when h= 2 * r
or h/d = 1
Is this result from theory or observation?
Is this because while h = 0.9 * r minimises the length of
wire and therefore the resistance but it is going to have
a higher voltage rise on each turn - increasing the effects
of inter turn capacitance?
Presumably then h = 2 * r gives the best comprimise between
wire resistance and the effects of inter turn capacitance.
Alan Sharp (UK)