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Re: Limiting Safety Gap Current



Um, um,,,,

> Original Poster: "Marco Denicolai" <Marco.Denicolai-at-tellabs.fi> 

<snip>
> An inductive load dissipates energy only in its resistive losses!
> Again, an ideal inductance DELAYS the current rising but allows it anyway
> to rise as much as it could without the inductance.

If CV^2 is constant and you increase L, what happens to I?  Another 
way of looking at it is I = V*SQRT(C/L)

> A resistor IMHO is the right solution.

I think so too.
Malcolm