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Re: Awg formula, was "New formula for secondary resonant frequency"
Original poster: "Mark Broker by way of Terry Fritz <twftesla-at-uswest-dot-net>" <broker-at-uwplatt.edu>
Tesla list wrote:
> Check your intermediate steps:
> awg = 1 + log(7.348e-3/wd)/0.115943 (use natural log)
> wd = 1.0236e-3
> 7.348e-3/wd = 7.17859
> log(7.17859) = 1.9711
> 1.9711/0.115943 = 17.0006
> 1 + 17.0006 = 18.0006
> Maybe you used 0.119543 instead of 0.115943 or something?
> Nope, the AWG sizes are fairly well defined, decreasing by a factor
> 1.122932 with each step. This factor is the sixth root of two,
> which means therefore that six AWG increments will exactly halve
> the wire size.
The formula for AWG is: D(inches) = .005 (39<root>92)^(36-N) where N is AWG
(4/0 is -4). (that's the 39th root of 92, btw)
I used this formula and the one supplied in an earlier email, and get the same
number (to within a few femptometers ;-).