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Re: Average, RMS and Power Factor made easy!



Original poster: "35045 by way of Terry Fritz <twftesla-at-uswest-dot-net>" <free0076-at-flinders.edu.au>



On Sat, 20 Jan 2001, Tesla list wrote:

> 
> 	For a square wave the average equals the peak equals the RMS.
> 
> Ed
> 

That's just plain wrong! If the average equals the peak you MUST have DC.
In that case the average=peak=RMS... You are thinking of DC not the square
wave we are discussing.

Have fun,
Darren Freeman