RE: TC quesions (sic)

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Loudner, Godfrey by way of Terry Fritz <twftesla-at-qwest-dot-net>" <gloudner-at-SINTE.EDU>

Hi

I think its a matter of taste. For someone like myself, who has low physical
intuition, I like energy arguments. It seems like I have a better sense of
the physical side if an energy approach is employed.  

Godfrey Loudner

> -----Original Message-----
> From:	Tesla list [SMTP:tesla-at-pupman-dot-com]
> Sent:	Saturday, January 26, 2002 11:20 AM
> To:	tesla-at-pupman-dot-com
> Subject:	Re: TC quesions (sic)
> 
> Original poster: "Ed Phillips by way of Terry Fritz <twftesla-at-qwest-dot-net>"
> <evp-at-pacbell-dot-net>
> 
> > Energy initially stored in the primary capacitor:
> > E1=0.5*C1*V1max^2
> > Maximum energy at the secondary capacitance:
> > E2=0.5*C2*V2max^2
> > By energy conservation, assuming low losses in the energy transfer:
> > E2=E1
> > And so:
> > V2max=V1max*sqrt(C1/C2)
> > But the two LC circuits are tuned to the same frequency:
> > L1*C1=L2*C2
> > and so:
> > C1/C2=L2/L1
> > and finally:
> > V2max=V1max*sqrt(L2/L1)
> > 
> > Antonio Carlos M. de Queiroz
> 
> 	Agree, with a very small quibble..  But isn't the expression using
> the
> capacitance ratio more instructive way to look what actually happens? 
> As you point out, the process starts with energy stored in the primary
> capacitor, and the maximum peak voltage in the secondary occurs when all
> of the energy from the primary capacitor is stored in the secondary
> capacitance.
> 
> Ed
> 
>