Re: Joules per bang...

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: DRIEBEN-at-midsouth.rr-dot-com 

Scot,

I may have contributed to your confusion. 5.265 x 120 = 675, not 795.
I must have typed the wrong figure in my calculator and arbitrarirly
sent it out w/out double checking my own math. Anyway, if you discharge
1000 joules (or watt-seconds) though a near zero Ohm load within .0001
seconds, then you will indeed get a 10 MW peak power within the .0001
seconds but it still averages out to 1000 watts per second. If you re-
peat this charge/discharge cycle ten times in 1 second, then you will
indeed have an avaerage power of 10 kW per second. But remember, we
were only talking about 5.625 watts (joules) per bang, not 1000. And
5.625 joules x 120 times per second = 675 average watts per second.
I believe someone else already pointed out in a previous post that
you were multiplying the 5.625 watts by 120 twice or in effect 120 sqd.
(14,400 x 5.625 does indeed equal 81,000 or 81 kW). I suppose that it
would be running 81 kW, per 2 minutes though,not per second ;^) Does
this make any sense now?

David Rieben

----- Original Message -----
From: Tesla list <tesla-at-pupman-dot-com>
Date: Monday, January 19, 2004 11:54 pm
Subject: Re: Joules per bang...

 > Original poster: BunnyKiller <bunikllr-at-bellsouth-dot-net>
 >
 >
 >
 > Tesla list wrote:
 >
 > >Original poster: DRIEBEN-at-midsouth.rr-dot-com
 > >Scot,
 > >
 > >Apparently, your math is off. 5.625 joules = 5.625 watts, therefore,
 > >if we fire 5.625 watts per bang at 120 a second, that yields a
 > much more
 > >conservative 795 watts per second. Can't quite figure out where you
 > >derived the 675 watts from the 5.625 joules :^/ My math ain't too hot
 > >either, but I think I figured this'n out ;^)
 > >
 > >David Rieben
 > >Memphis, TN
 >
 >
 > hmmm   now Im lost again and I thought I had this figured out...
 > ok as I
 > see it
 >
 > J= the amount of energy a capacitor of a certian size and voltage
 > can
 > produce...
 >
 > W= the amount of power dissapated over a time interval...
 > and 1J will produce 1W in 1 second
 > am I right so far??
 >
 > okay   if we have our 2000uF cap charged to 1000V   that should
 > give us
 > 1000J...
 > and if discharged thru a resistor (ummm 1000ohms?estimating
 > here...) that
 > will drain the cap in 1 second approximately (ignoring the
 > logorithmic
 > curve), should produce 1000W of  power/heat/energy... in other
 > words we
 > need a 1000W  1 ohm resistor to handle the current....safely...
 >
 > if discharged thru a near 0 ohm resistor taking about .0001
 > seconds that
 > should produce about 10MW of power in that time duration...peak
 > power...
 > now if we were to do this 10 times a second...  there should be
 > 10KJ of
 > energy used   ergo 10KW avg power per second
 >
 > am I still good here?
 >
 > Scot D
 >
 >
 >
 >
 >
 >
 >