Re: Peak Primary Current

["Tesla list" <tesla@xxxxxxxxxx>]

Original poster: "Bob (R.A.) Jones" <a1accounting@xxxxxxxxxxxxx>




> Original poster: "Jim Lux" <jimlux@xxxxxxxxxxxxx>


> This is the peak current on the first half cycle.  If the pulse were a nice
> rectangular envelope (which it is not), you'd still have to divide by 1.414
> to get the rms current, which is what you should be using for power
> dissipation calculations. There are handbook tables for damped sinusoid rms
> values (or you can solve them from first principles... it's
> I=exp(-k*t)*cos(omega*t) for a damped sinusoid in an RLC)... watch out
> though, TC's don't necessarily have nice exponential decay. See below.
> > This assumes voltage drop across spark gap is neglible which I guess is
> > true once the current flow is established.

Assuming the secondary is in place an its all tuned correctly. Ignoring 
losses and higher order terms, the envelope is cosine and if its an integer 
of a 1/4 cycle the rms value is half the peak.
ie 1/1.414 * 1/1.414.

Of cause the actually envelope is determined by quench, streamer loading 
and circuit losses (SG etc) as you suggested.



Robert (R. A.) Jones
A1 Accounting, Inc., Fl
407 649 6400