Re: [TCML] Power Factor Correction

I see lots of other replies but instead of looking at them let me remind you that with a capacitor across the output terminals and sparking going on the rules are altogether different from with a resistive load.

Ed

On 12/3/2016 2:32 PM, Ronald Reeland wrote:
Hi:

I have been researching adding an A.C. power factor correction capacitor across the 120 volt primary of a 15,000 volt, 30 milliamp secondary neon sign transformer for a spark gap Tesla coil application.

It appears that the power factor of an ordinary transformer without a built-in correction capacitor is 40 to 50 %. That means that the input volt/amps is around twice that of a "perfect" power factor of 100%. Of course we can never achieve a perfect 100%.

But it appears a person can attain a 90% or greater power factor thus reducing the primary input current draw by calculating an approximate value of correction capacitor.

Here is a  power factor correction capacitor formula that I found on the web and in Brent Turner's book;  "The Tesla Coil Book", how they work & how they are built" :

PF Capacitor=  "corrected kVA" x  (10^9 divided by 2TT x Frequency x primary volts^2) or in a more compact form : C=kVA (10^9/2TT f e^2).

There is a partial chart in Brent's book titled" PF-Corrected Transformer ratings" and complete charts on the web for various transformer output volts and current. It appears that the "corrected" output kVA is one half in some instances and 55% or so in other cases.So if I have computed the formula properly, a 15,000 volt, .030 amp transformer requires a 46 ufd A.C. capacitor across the transformer primary. This is based on the charts "corrected kVA" of .250. (The un-corrected kVA would be 15,000 x .030 or .450 kVA.)

1. I am asking for confirmation that all of above is true and that I manipulated the formula properly.

2. I assume that since the formula deals with secondary output, the lowered kVA is reflected in the 120 volt primary input and the current draw there is reduced in proportion.

3. Also, is the formula a starting point for adjusting the capacitor value higher or lower with an A.C. ammeter in the primary until the lowest input amperage is achieved?

4. I also assume the secondary must be under load while fine tuning the power factor capacitor value.

5. I have some 56 ufd, 250  volts A.C. motor-run capacitors (EPCOS brand) that I would like to try.

Any help or corrections to my assumptions would be greatly appreciated.

Thanks,

Ron Reeland

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