Re: Inductance of a conical coil

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "by way of Terry Fritz <teslalist-at-qwest-dot-net>" <Mddeming-at-aol-dot-com>

In a message dated 2/23/03 10:39:43 AM Eastern Standard Time, 
tesla-at-pupman-dot-com writes:



>This formula weights the horz and vert Wheeler equations, but is poor in
>accuracy. I've added my own "weighting" to this of which the final L above
>is multiplied by a factor based on the angle.
>
>I then have:
>L = [SQRT[(L1*Sin(X))2 + (L2*cos(X))2] ] * my factor
>
>First I find the cosine and sine of the angle in radians and denote them as
>"sina" and "cosa". My factor is then: ((cosa^2+sina^2)/SQRT(cosa+sina))*2

Hi Bart,
        Using the elementary trigonometric identity: S^2(a) + C^2(a) = 1, 
the formula immediately reduces to :
1/(sqrt(sina +cosa)*2 = 2/sqrt(sina+cosa)
However, for the values you gave:sina = 0.939693, cosa = 0.342020
2*(!/sqrt(0.939693 +  0.342020)) = 1.766585254 exactly double what you stated:

My factor then = 0.883292708

Think you need a slight revision

Matt D.