Re: [TCML] Disassebling a huge transformer

[Mddeming@xxxxxxx]

Hi Bama,
 
X(L)=E/I and L= X(L) / (2 pi f). At 60 Hz 2 pi f = ~377.
 
Matt D.
 
 
In a message dated 7/22/2008 9:04:22 A.M. Eastern Daylight Time,  
bamacoiler@xxxxxxxxx writes:

How can  I figure out the inductance besides using lcr meter?
Bamacoiler

On  Mon, Jul 21, 2008 at 9:41 PM, bartb <bartb@xxxxxxxxxxxxxxxx>  wrote:

> Hi Garry,
>
> Lamination disassembly is a  daunting task (BTDT). But before you go tearing
> the xfmr apart, try to  figure out the inductance. The DC resistance is not
> what you need to  look at. It's the inductance which performs the current
> limiting  (i.e., inductive ballast such as welders, variacs, etc..). If it's
> at  least 20 mH, your in business as is. If you can get to the internal
>  ribbon layers, you can attach wires which you can run to a tap to vary  the
> inductance. Sure beats the alternative of tear  down.
>
> Regards,
> Bart
>
> garry neeley  wrote:
>
>> It is not a typical 2 winding transformer.  It  has 1 winding with taps but
>> its not wound with wire.  It's  wound with thick copper ribbon about 4-6
>> inches wide.  It's a  huge current type transformer.  It just wouldn't cut
>>  it
>> as is.  Almost no dc resistance.
>>
>>  On Mon, Jul 21, 2008 at 10:19 AM, Chip Atkinson <chip@xxxxxxxxxx>  wrote:
>>
>>
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