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RE: [TCML] new toroid capacitance
Ahh, now it's making more sense. :)
Still not a bad pf value, though, even if it's not where I was hoping.
Thanx.
> -----Original Message-----
> From: tesla-bounces@xxxxxxxxxx [mailto:tesla-bounces@xxxxxxxxxx] On Behalf Of Bob Wroblewski
> Sent: March 18, 2011 9:34 AM
> To: Tesla Coil Mailing List
> Subject: Re: [TCML] new toroid capacitance
>
> Hi Rev Fuzzy,
>
> Okay, let's try this again.
>
> The cross sectional area of your toroid ring is about 4.1875 x 2 = 8.375 from
> the drawing pdf. So assuming that the area of a circle is determined by pi
> (r^2) and using 8.375 as the desired area, we get 1.633 as an equivalent
> circular toroid ring radius or 3.266 as an equvalent circilar toroid ring
> diameter.
>
> Assuming that we keep the same 11.75 overall diameter dimension from the drawing
> pdf. With an equivalent 3.266 diameter toroid ring we can calculate the two
> inputs for the QTC spreadsheet.
>
> They are D (maj) 8.484 and D (min) 3.266 for a result of 13.1 pf as calculated
> by QTC.xls
>
> That should be good enough as a ballpark figure. Not quite the value you were
> hoping for but YMMV.
>
> Regards,
> Bob Wroblewski
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