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Re: Bleeder resistor



Original poster: "Crow Leader by way of Terry Fritz <twftesla-at-qwest-dot-net>" <tesla-at-lists.symmetric-dot-net>

I prefer to short out any items that can bite with a hotstick and then
jumper then with a shorting cable before playing. Even if you sit around
waiting for bleeder resistors to do their job you should still short out
what you are working with before playing with it. It's dangerous to just
assume safety devices are working properly.

KEN

----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Friday, May 31, 2002 12:16 PM
Subject: Re: Bleeder resistor


> Original poster: "Jim Lux by way of Terry Fritz <twftesla-at-qwest-dot-net>"
<jimlux-at-earthlink-dot-net>
>
> P = E^2/R... 20E3*20E3/50E6 = 400/50 = 8W
>
> As a practical matter, you'll probably be more limited by HV breakdown
over
> the resistor.  A 2W carbon resistor is probably good for 2 kV, breakdown
> wise.  So a string of 10 resistors: 5 Meg at 2W, would be a likely
candidate...
>
> For what it's worth, none of this stuff is critical.. It's always a
> tradeoff between power dissipation in the bleeder and "time til safe"....
> Say you make it a string of 10Meg resistors instead (100Meg total)... Now
> the dissipation is only 4 W, and you've doubled the time to 1 minute..
>
> By the way, a minute (or even 30 seconds) is a VERY long time to wait when
> you want to work on something.  You could probably afford to burn up 20-30
> Watts in the bleeders (not on a small NST coil, though, where this would
be
> 10% of the power!) and cut the "time to 50V" down to 10 seconds or so..
>
> Tesla list wrote:
> >
> > Original poster: "by way of Terry Fritz <twftesla-at-qwest-dot-net>"
> <Dan_Gallagher%PULSARNOTES-at-pulsartech-dot-com>
> >
> > Hi Jim, Terry and all,
> >
> > Jim, thanks for the info on bleeders. You say 50megohms for a .01uf cap.
> > What wattage resistor would this be?
> >
> > Thanks
> >
> > getting closer..............
> > Dan
> > Ft. Lauderdale
>
>
>
>