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OK, so in a normal (non-elevator) situation, the time it takes for a projectile to reach it highest point is just vi/9.8, which here is 0.5 sec.

To me, the answer to both questions is 0.5 sec. Am i missing something here?

Regards

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- Thread starter redshift
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- #1

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OK, so in a normal (non-elevator) situation, the time it takes for a projectile to reach it highest point is just vi/9.8, which here is 0.5 sec.

To me, the answer to both questions is 0.5 sec. Am i missing something here?

Regards

- #2

arildno

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- #3

NateTG

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Alternatively consider the following:

If the ball is moving down at 1 m/s w.r.t. to the elevator it has passed it's highest point w.r.t. the elevator, but it's still going up at 1.5 m/s relative to the floor, so it has not passed it's highes poin w.r.t. the floor. Therefore the two times must be different.

- #4

arildno

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Hence, for a stationary observer outside the elevator, the highest point the ball will reach, will in all probability be at some time when the elevator has reached the top floor (of the building it's in).

I think, however that the intended answer is along NateTG's lines...

- #5

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I guess I misunderstood the meaning of "highest". Thanks

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